show that the dimensions of cuboid are x, x-2 and x-3 whose volume x³-5x²+6x
Answers
Answer:
Step-by-step explanation:
we know that the area of a cuboid id length * width * height
therefore putting dimensions in the formula gives us
x³-5x²+6x = (x)(x-2)(x-3)
x³-5x²+6x= (x²-2x)(x-3)
x³-5x²+6x = x³ - 3x² - 2x² + 6x
x³-5x²+6x = x³ - 5x² + 6x
hence LHS = RHS (i.e. the volume is equal to the product of three dimensions)
Answer:
Show that the dimensions of the cuboid are x x-2 and x-3 whose volume is x^(3)-5x^(2)+6x.
Step-by-step explanation:
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