show that the effective resistance of a series combination is Rs=R1 +R2 +R3........... +Rn
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in the series combination the total voltage is sum of voltages used by all resistances
so v = V1 + V2 + V3 .......vn
IR = IR1 + IR2 + IR3 .......IRn
since current is constant so
IR = I( R1+ R2+R3......Rn)
cutting I from both sides
R = R1+ R2 + .......Rn
so v = V1 + V2 + V3 .......vn
IR = IR1 + IR2 + IR3 .......IRn
since current is constant so
IR = I( R1+ R2+R3......Rn)
cutting I from both sides
R = R1+ R2 + .......Rn
Answered by
0
In a series combination
Veff.= V1+V2+V3+...
IR eff.= IR1+IR2+IR3+...
Now as in a series combination current is constant,
Therefore,
IR eff.= I( R1+R2+R3+...)
Therefore,
R eff.= R1+R2+ R3+...
garvit115829:
thank you
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