Question

Show that the efficiency of the Rankine cycle is given by n=<h1-h2)-(h4-h3)/(h1-14), all the
characters have their usual meaning. ​

Answer 1

Answer:

⇝ We Know :-

Mass of Magnesium (Mg) = 24 u

Mass of Sulphur (S) = 32 u

Mass of Oxygen (O) = 16 u

Mass of Hydrogen (H) = 1 u

⇝ Calculating Molar Mass of MgSO₄.7H₂O :

Molar Mass = Mass of Mg + Mass of Sulphur + 11 × Mass of Oxygen + 14 × Mass of Hydrogen.

❒ Using Above written Masses :

\begin{gathered}\text{ Molar mass} = 24 + 32 + 11 \times 16 + 14 \times 1 \\ \end{gathered} Molar mass=24+32+11×16+14×1

\begin{gathered} = 24 + 32 + 176 + 14 \\ \end{gathered}=24+32+176+14

\large\red{ \bf = 246 \: u}=246u

⇝ Calculating Molar Mass of 7H₂O :

Molar Mass = 7 × ( 2× Mass of Hydrogen + Mass of Oxygen)

❒ Using Respective Masses :

\begin{gathered}\text{ Molar mass} = 7 \times(2 \times 1 +16)\\ \end{gathered} Molar mass=7×(2×1+16)

\begin{gathered} =7\times( 18) \\ \end{gathered}=7×(18)

\large\red{ \bf = 126 \: u}=126u

⇝ Calculating Reqrd. percentage :-

\begin{gathered} \purple{\sf \small \% \: of \: water = \frac{mass \: of \: water \: in \: molecule}{mass \: of \: molecule \: } \times 100} \\ \end{gathered}%ofwater=massofmoleculemassofwaterinmolecule×100

\begin{gathered} = \frac{126}{246} \times 100 \\ \end{gathered}=246126×100

\begin{gathered} = 0.5121 \times 100 \\ \end{gathered}=0.5121×100

\bf= 51.21\%=51.21%

Hence,

\large\underline{\pink{\underline{\frak{\pmb{Required \: \% = 51.21\%}}}}}Required%=51.21%Required%=51.21%