Question

show that the equation of second degree 5 x 2-2xy+5y2+2x-10y-7=0

Answer 1

6,please mark me down as a brainilist

Answer 2

Answer with explanation:

The Second degree equation is

$5 x^2-2 x y+5 y^2+2 x-10 y-7=0$

The general equation representing Conic is

 $Ax^2+By^2+ 2 H x y +2 G x +2 F y+C=0$

→Comparing with above given equation,

Gives, A=5, B=5, C= -2, G=1, F=-5, C= -7,H=-2

There is a term containing ,x y

if you will look at the general equation of other conics,you will find that none of them contains term containing , x y.

So, The following equation of Conic represents Pair of straight lines.

In General form, it can be written as

$Ax^2+By^2+ 2 H x y +2 G x +2 F y+C=(ax+by+c)\times(p x+q y+r)$