Show that the equation,
for every real value of 'x' there is a real value of 'y' , and for every real value of 'y' there is a real value of 'x'.
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Hope this solutio will help you
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mkrishnan:
question is ok bro please make correction
Answered by
3
Answer:
Step-by-step explanation:
x^2 -3xy +2y^2 = [x-2y] [x-y]
x^2 -3xy +2y^2 -2x-3y -35 = [x-2y+m ] [x-y+n]
now
m+n = -2
-m-2n = -3
adding -n = -5
n=5
then m= -7
x^2 -3xy +2y^2 -2x-3y -35 = [x-2y-7 ] [x-y+5]
this is a pair of st lines [ two lines ]
so all real x we find 2 real values y [except the point of intersection]
and converse also true
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