Question

Show that the equation x? + 6x +6=0 has real roots and solve it.​

Answer 1

Step-by-step explanation:

⇒ The given equation is ∣x∣ 2

+∣x∣−6=0 ---- ( 1 )

⇒ When x≥0, then ∣x∣=x, so equation ( 1 ) becomes,x 2 +x−6=0

⇒ x 2 +3x−2x−6=0

⇒ x(x+3)−2(x+3)=0

⇒ (x+3)(x−2)=0

⇒ x=−3,2

When x<0, then ∣x∣=−x, so equation ( 1 ) becomes,

x 2 −x−6=0⇒ x 2

−3x+2x−6=0

⇒ x(x−3)+2(x−3)=0

⇒ (x−3)(x+2)=0

⇒ x=3,−2

⇒ Sum of the roots =−3+2+3−2=0

∴ Here, roots are real and equal.

Answer 2

Answer:

6x +6 =0

=> 6x = -6

=> x = -6/6

=> x = -1

Step-by-step explanation:

hope its helpful