Question

Show that the equation x square + x - 1 is equals to zero has real and distinct roots for all real values of x

Answer 1

eqn. is

${x}^{2} + x - 1 = 0 \\ here \\ d = {1}^{2} - 4(1)( - 1) = 5 > 0 \\ hence \: the \: equation \: has \: real \: and \\ distinct \: roots$