Question

show that the equations are dimensionally correct please answer with a picture
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Answer 1

Answer:

A.

G = [M1 L1 T-2] × [L]2 × [M]-2 = [M-1 L3 T-2]. Therefore, the gravitational constant is dimensionally represented as M-1 L3 T-2.

Dimensional Formula of Force= M1L1T-2.

B.

We know ForceF=mass×acceleration----------(1)

And given ForceF= mv^2/r----------(2)

Equating 1 and 2 dimensionaly we get ,

ma= mv^2/r

MLT−2=ML2T−2L−1

MLT−2 =MLT−2