Show that the equivalent resistance of three resistors connected in series is equal to the sum of the resistance of the individual resistors
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IR1 = IR2 = IR3 = IAB. Here the resistors R1, R2 and R3 each valued 1 Ω, 2 Ω and 3 Ω are in series connection. Same current will flow through all the resistors since they are connected in series. The total resistance of the circuit is equal to sum of individual resistances.
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