show that the exterior angle of a triangle is equal to the sum of two opposite interior angle
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in a triangle..
angle 1 + 2 + 3 =180..
angle 3 +4 = 180 (linear pair)
1 + 2 +3 = 3 +4
1 +2 =4 .
angle 1 + 2 + 3 =180..
angle 3 +4 = 180 (linear pair)
1 + 2 +3 = 3 +4
1 +2 =4 .
Answered by
8
aloha user!
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given: triangle ABC
to prove: angle A + angle B = angle ACD
proof:we know that the sum of angles of a triangle is 180°.
also angle ACD and angle ACB form a straight angle.
so,
angle ACD + angle ACB = 180°.------(1)
angle A + angle B + angle ACB = 180°-------(2)
as (1) and (2) are equal we can write:
angle ACD + angle ACB = angle A + angle B + angle ACB
( angle ACB - angle ACB = 0 )
angle ACD = angle A + angle B
hence proved.
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hope it helps :^)
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given: triangle ABC
to prove: angle A + angle B = angle ACD
proof:we know that the sum of angles of a triangle is 180°.
also angle ACD and angle ACB form a straight angle.
so,
angle ACD + angle ACB = 180°.------(1)
angle A + angle B + angle ACB = 180°-------(2)
as (1) and (2) are equal we can write:
angle ACD + angle ACB = angle A + angle B + angle ACB
( angle ACB - angle ACB = 0 )
angle ACD = angle A + angle B
hence proved.
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hope it helps :^)
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