show that the following numbers are irrational 6+root 2
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let us assume that 6+√2 is rational
⇒6+√2=p/q
⇒√2=p/q-6
⇒√2=p-6q/q
irrational=rational
which is a contradiction
∴our assumption is wrong
6+√2 is irrational
⇒6+√2=p/q
⇒√2=p/q-6
⇒√2=p-6q/q
irrational=rational
which is a contradiction
∴our assumption is wrong
6+√2 is irrational
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answer is in pic...................
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shalini28:
mark as best
thank u
actually i have learnt like that and it is the simpliest way
ok
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