Show that the following points are the vertices of a square a(3,2) b(0,5)c(-3,2)d(0,-1)
Answers
Answered by
0
Answer:
by finding the length of each points will help you
Answered by
1
Answer:
ab= √(3^2 +(5-2)^2= √18
bc = √3^2 +(2-5)^2 = √18
cd = √3^2 +(-1-2)^2 = √18
ca = √3^2 +(-1-2)^2 = √18
All sides are equal
ac = √(-3-3)^2 + (2-2)^2 = √36= 6
bd = √(0 -0)^2 + (-1-5)^2= √36 = 6
diagonals are equal
So abcd is a square
Similar questions