Question

Show that the following points form a right angled triangle.

(10, 0), (18, 0) and (10, 15)

Answer 1

In right angled Δ,
hypotenuse is greater than perpendicular,and perpendicular is greater than the base,
Now,let us name the points A(10,0),B(18,0),C(10,15)
By knowing the difference between this points we'll get,
AB=(18-10)+(0-0)=8 units(Perpendicular)--------------(As mentioned above)
BC=(10-18)+(15-0)=7 units(Base)------------------------(As mentioned above)
AC=(10-10)+(15-0)=15 units(hypotenuse)-------------(As mentioned above)
here AC>AB>BC
Hence proved that points are the edges of right angled Δ.