Show that the following points form equilateral triangale
A=(a,0) B= (-a,0) c=(0,a root 3
Answers
Answered by
0
Given A(a,0) B(−a,0) C(0,a
3
)
AB=
(a−(−a))
2
+(0−0)
2
=
4a
2
=2a
BC=
(0−(−a))
2
+(a
3
)
2
=
4a
2
=2a
CA=
(0−(−a))
2
+(a
3
)
2
=
4a
2
=2a
∴ AB= BC = CA
Hence it is an equilateral triangle
Answered by
0
Answer:
Sure I will answer it for you mate,
A = (a, 0) , B = (-a, 0) , C = (0, aroot 3)
AB = BC = AC
AB = Root over (-a-a) ² + (0-0)² = 2a
BC = Root over (a root 3²-0²) + (0+a²) = 2a
AC = Root over (0-a²)+(aroot 3²-0²) = 2a
AB = BC = AC = 2a
All sides are equal
It is equilateral Triangle..
Hence proved..
Please mark it as brain list please...
Similar questions