Show that the following points taken in order form an isosceles triangle.
(i) A (5,4), B(2,0), C (–2,3) (ii) A (6,–4), B (–2, –4), C (2,10)
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- 1/2(x1+(y2-y3)+x2(y3-y1)+x3(y2-y1)these a formula please do learn then solves the sum now let start
- 1/2(
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triangle are isosceles
Step-by-step explanation:
A (5,4), B(2,0), C (–2,3)
AB = √(5-2)² + (4-0)² = √9 + 16 = √25 = 5
AC = √(5-(-2))² + (4-3)² = √49 + 1 = √50 = 5√2
BC = √(2-(-2))² + (0-3)² = √16 + 9 = √25 = 5
AB = BC
hence triangle is isosceles
A (6,-4), B(-2,-4), C (2,10)
AB = √(6-(-2))² + (-4-(-4))² = √8² = 8
AC = √(6-(2))² + (-4-10)² = √16 + 196 = √212 = 2√53
BC = √(-2-(2))² + (-4-10)² = √16 + 196 = √212 = 2√53
AC = BC
hence triangle is isoscelles
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