show that the following system of the equation has a unique solution and hence find the solution of the given system of equation x/3+y/2=3;x-2y=2
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Step-by-step explanation:
x-2y=2
x=2+2y
Now,
x/3+y/2=3
2+2y/3+y/2=3
2 (2+2y)+3y/6=3
2 (2+2y)+3y=18
4+4y+3y=18
4+7y=18
7y=14
y=2
x-2y=2
x-2 (2)=2
x-4=2
x=6
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