Show that the force on each plate of a parallel plate capacitor has a magnitude equal to (½) QE, where Q is the charge on the capacitor, and E is the magnitude of electric field between the plates. Explain the origin of the factor ½.
Answers
Answered by
4
Energy on the capacitor = 1/2 QV= Force on each plate × distance of separation
or 1/2 QEd = Force × d
or Force = 1/2 QE
Hope it helps u
or 1/2 QEd = Force × d
or Force = 1/2 QE
Hope it helps u
Similar questions