Show that the frequencies of first three harmonics of an open organ pipe are in the ratio 1 : 2 : 3
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First Harmonic or Fundamental Frequency :
First Harmonic should at least have an antinode at each end with node included between them.
Vibrating length , l=λ/2
⇒λ=21
n1=V/λ where V is the velocity of sound in air.
∴ n₁=V/2l --------------(1)
Second harmonic :
Second harmonic should have atleast one node and antinode between than the fundamental frequency .
Vibrating length, l=λ
Then n2=V/λ=V/l=2V/2l
∴n2=2n1----------(2)
Third harmonic :
Third Harmonic should will have three nodes and fore antinodes
Vibrating lenth, l=3λ/2
⇒λ=2l/3
then
n3=3V/2l
∴n3=3n1----------(1)
By comparing equation 1, 2 and 3 we say that....
frequencies of first three harmonics of an open organ pipe are
in the ratio 1 : 2 : 3
First Harmonic should at least have an antinode at each end with node included between them.
Vibrating length , l=λ/2
⇒λ=21
n1=V/λ where V is the velocity of sound in air.
∴ n₁=V/2l --------------(1)
Second harmonic :
Second harmonic should have atleast one node and antinode between than the fundamental frequency .
Vibrating length, l=λ
Then n2=V/λ=V/l=2V/2l
∴n2=2n1----------(2)
Third harmonic :
Third Harmonic should will have three nodes and fore antinodes
Vibrating lenth, l=3λ/2
⇒λ=2l/3
then
n3=3V/2l
∴n3=3n1----------(1)
By comparing equation 1, 2 and 3 we say that....
frequencies of first three harmonics of an open organ pipe are
in the ratio 1 : 2 : 3
Answered by
2
it is true write the first second and third harmonic s of open pipe and it will come like f1= v/2l____1
f2=2f1______2
f3=3f1_______3.
so hope this is helpful...
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