Question

Show that the frequency of the first line in the Lyman series is equal to the difference between the limiting frequencies of Lyman and the Balmer series.​

Answer 1

Answer:

The 'series limit' refers to the 'shortest wavelength'.

f=k(n121−n221)

Here, k is a constant.

For the series limit of Lyman series,

n1=1

n2=∞

For the series limit of Balmer series,

n1=2

n2=∞

Thus, the difference in the frequencies of the series of Lyman series and Balmer series is equal to the frequency of the first line of the Lyman series.