Show that the function defined by f(x) = sinx^2 is a continuous function.
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Answer:
Let p(x)=sinx;9(x)=x ^2 [x∈R]
Both p(x) and q(x) are always continuous.
So, p(q(x)) is always continuous
So, sin(x^2) is a continuous function.
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Given : f(x) = sinx²
To Find : Show that function is continuous
Solution:
f(x) = sinx²
f(t) =sin t
where t = x²
f(x) = sin x is a continuous function for x ∈ r
t = x²
t ∈ ( 0 , ∞) for x ∈ R
Hence f(t) = sin t is continuous as t ∈ ( 0 , ∞) ⊂ x ∈ R
Hence
f(x) = sinx² is continuous function
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