show that the function f(X) = 3x + 2 is one - one and onto
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hello friend...!!!
according to the question we should prove f(x) is one - one and onto,
1) to prove it is one - one :
let, f(x1) = f(x2)
implies, 3x1 +2 = 3x2 + 2
implies, x1 = x2
therefore it is one - one function.
2) to prove it is onto function :
let y = 3x + 2
implies, x= y - 2 / 3
for all x € R there exist at least one X in R such that,
f ( x) = f ( y - 2 / 3 )
= 3 ( y - 2 / 3 ) + 2
= y -2 +2
= y .
therefore f( x) is onto function.
_________________________________
hope it helps....!!!!
according to the question we should prove f(x) is one - one and onto,
1) to prove it is one - one :
let, f(x1) = f(x2)
implies, 3x1 +2 = 3x2 + 2
implies, x1 = x2
therefore it is one - one function.
2) to prove it is onto function :
let y = 3x + 2
implies, x= y - 2 / 3
for all x € R there exist at least one X in R such that,
f ( x) = f ( y - 2 / 3 )
= 3 ( y - 2 / 3 ) + 2
= y -2 +2
= y .
therefore f( x) is onto function.
_________________________________
hope it helps....!!!!
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