show that the function f(x) =logx÷x for x isnot equal to 0 is maximum at x = e
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f'(x)= 1-log(x)/x^2
for f'(x)=0
1- log(x)=0
log(x)=1
x=e
to find out if this point is of minima or maxima find f''(x) if its value at x=e is -ve then x=e is the point of maxima
f'(x)= 1-logx/x^2
f''(x)= -x -2x(1-logx)/x^4
at x=e
f''(x)= -1/e^3 hence point of MAXIMA
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