Show that the function f (x)=(x-1)e^x+1 is an increasing function
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Answer:
Step-by-step explanation:
f (x)=(x-1)e^x+e^x {product rule}
=xe^x
=e^x is >0 all x E r
and x >0 because it is given
its product will be >0 so
f (x) >0 for all x>0
so f (x) is an increasing function
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