Question

show that the function y=x^3-3x^2 +3x+7 has neither maximum nor minimum at x=1.​

Answer 1

Step-by-step explanation:

Derive and see where local minima and maxima are:

y′=3x2−6x+6=3(x2−2x+2)=3[(x−1)2+1]>0∀x∈R

Which means that y is strictly monotonic.