Question

show that the function y=x³-3x²+5 has a maximum value at x=0 and a minimum value at x=2​

Answer 1

Answer:

Given, Function,y=x

3

−3x

2

+6

So for that, we have to find the critical value of y so, differentiate y respect to x

y

′

=3x

2

−6x=3x(x−2)=0

So, X is either be 2 or 0. these are the critical values.