. Show that the half life period of a 1st order reaction is independent of the initial concentration of the reactant. The rate constant for an isommerisation reaction, A longrightarrow B is 4.5 * 10 ^ - 3 * m * i * n ^ - 1 . If the intial concentration of A is IM, calculate the rate of reaction after 1 hour. [Antilog (-0.1172)=0.7635];
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Answered by
2
Answer:
Correct option is
A
3.44×10
−3
molL
−1
min
−1
Rate constant in min
−1
indicates that, the reaction is of 1st order. Hence, k=
t
2.303
log
[R]
[R]
0
4.5×10
−3
min
−1
=
60min
2.303
log(
[R]
1
)
log[R]=−0.1172=
1
.8828
or [R]= antilong
1
.8828
[A]=0.7635molL
−1
; this is the concentration after 60 min or one hour.
So, rate after 1 hour Rate=K[A]=4.5×10
−3
×0.765
=3.44×10
−3
molL
−1
min
−1
Answered by
0
Answer:
for an isommerisation reaction, A longrightarrow B is 4.5 * 10 ^ - 3 * m * i * n ^ - 1 . If the intial concentration of A is IM, calculate the rate of reaction after 1 hour. [Antilog (-0.1172)=0.7635];
Explanation:
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