Question

Show that the line joining the points (-1, 2) and (3, 2) is parallel to the line
points (-5, 0) and (4,0).​

Answer 1

Answer:

Step-by-step explanation:

let P≡(-1, 2)≡(x1,y1)

    Q≡(3, 2)≡(x2y2)

∴slope of line pq = y2-y1/x2-x1

                            =2-2/3-(-1)

                            =0/3+1

                            =0/4

                            =0         -(i)

let, A≡(-5, 0)≡(x1,y1)

     B≡(4,0)≡(x2y2)

∴ slope of line AB=  y2-y1/x2-x1

                             = 0-0/4-(-5)

                             =0/4+5

                             =0/9

                             =0          -(ii)

∴from (i) &(ii) we get that

slope of line PQ =slope of line AB

∴line joining the points (-1, 2) and (3, 2) is parallel to the line

points (-5, 0) and (4,0)

it can be made using a graph tooo