Question

show that the line through the points (-2,6) and (4,8) is perpendicular to the line through the points (3,-3) and (5,-9)​

Answer 1

Answer:

Step-by-step explanation:

Let the point are:

A( -2,6), B(4,8)

So gradient of AB

m1=y2-y1/x2-x1

=8-6/(4+2)=2/6=1/3

Other pair is C(3,-3) D(5,-9)

m2=(-9+3)/(5-3)=-6/2=-3

m1*m2=(1/3)(-3)=-1

so m1m2=-2

Thus AB⊥CD

Answer 2

Answer:

m1 = 1 / 3

m2 = 3

m1 / m2 = m2 / m1 = 1

so AB perpendicular CD

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