show that the line through the points (-2,6) and (4,8) is perpendicular to the line through the points (3,-3) and (5,-9)
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Answered by
2
Answer:
Step-by-step explanation:
Let the point are:
A( -2,6), B(4,8)
So gradient of AB
m1=y2-y1/x2-x1
=8-6/(4+2)=2/6=1/3
Other pair is C(3,-3) D(5,-9)
m2=(-9+3)/(5-3)=-6/2=-3
m1*m2=(1/3)(-3)=-1
so m1m2=-2
Thus AB⊥CD
Answered by
0
Answer:
m1 = 1 / 3
m2 = 3
m1 / m2 = m2 / m1 = 1
so AB perpendicular CD
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