Question

show that the line x+7y=23 and 5x+2y=16 intersect at the point (2,3)

Answer 1

$x + 7y = 23.....(1) \\ 5x + 2y = 16.....(2) \\ multiply \: (1) \: by \: 5 \\ 5x + 35y = 115 \\ 5x + 2y = 16 \\ subtract \\ 0 + 33y = 115 - 16 \\ 33y = 99 \\ y = 3 \\ put \: in \: (1) \\ x + 7y = 23 \\ x + 7(3) = 23 \\ x = 2$
point is (2,3)

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