Question

Show that the lines 3x+4y = 13, 2x-7y+1 = 0 and 5x-y=14 are concurrent.​

Answer 1

Answer:

answer is 5

Step-by-step explanation:

The lines 3x + 4y = 13, 2x – 7y = -1 and ax – y – 14 = 0 are concurrent.

⇒ 3(98 + 1) – 4(-28 – a) – 13(-2 + 7a) = 0

⇒ 3(99) + 112 + 4a + 26 – 91a = 0

⇒ 297 + 112 + 26 + 4a – 91a = 0

⇒ 435 – 87a = 0

⇒ -87a = -435 ⇒

a = −435−87−435−87 = 5