Show that the magnitude of the cross product of two vectors is equal to the 2*area of triangle formed by the two vector
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The cross product of two vector represent the area of the parallelogram formed by them . Now consider a parallelogram OKLM . whose adjecent sides OK and OM as shown in fig
As we know that
Area of parallelogram = base × height …………(1)
So in the figure base = OK = A ( VECTOR )
Height = Bsin ¥
So putting the value in equation (1) we get
Area of parallelogram = AB sin¥ = A× B = cross product of two vector A and B
I try to explain you in easiest method
My figure is not much good but you can understand ( smiling )
912 Views · View Upvoters · Answer requested by Aditi Kachhawaha
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Faizan Ahmed
Vivek
Vivek
Answered Sep 20, 2017
A2A
Because are of a parallelogram is given by ABsinθ
Where A and B are two sides of parallelogram and θ being the angle between them
But, |A⃗ ×B⃗ |=|A||B||sinθ|
Hope you got the point
VM
Step-by-step explanation:
Area of a parallelogram.
area of a parallelogram = Base × height.
= |A| × |B| sin Q
= |A| |B| sin Q
Area of a parallelogram =|A×B|
Hope you understood.
thank you!