Question

show that the maximum value function X + 1 by X is less than its minimum value

Answer 1

Answer:

Step-by-step explanation:

(x)=x+1xf(x)=x+1x

⟹f′(x)=1–1x2⟹f′(x)=1–1x2

Critical point(s):

f′(x)=0f′(x)=0

1−1x2=01−1x2=0

⟹x=±1⟹x=±1

f′′(x)=2x3f″(x)=2x3

f′′(−1)=−2,f′′(1)=2f″(−1)=−2,f″(1)=2

Maximum value of f(x):f(−1)=−2f(x):f(−1)=−2

Minimum value of f(x):f(1)=2