show that the nth odd natural is 2n-1
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AP :- 1, 3, 5, 7.........
a = 1 d = 2
an = a + (n-1)d
= 1 + (n-1)2
= 1 + 2n - 2
= 2n - 1
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a = 1 d = 2
an = a + (n-1)d
= 1 + (n-1)2
= 1 + 2n - 2
= 2n - 1
Hope it helps.
Mark me as brainlist.
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A box of 600 electric bulbs contains 12 defective bulbs one bulb is taken out at random from the box what is the probability that it is a non-defective bulb
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