Question

show that the number 3n cannot end with the digit 0 for any natural number. ​

Answer 1

Answer:

sorry I don't now this ..

Answer 2

Answer:

Wait I will answer u in detail

Step-by-step explanation:

so if the question is 3 n then

(3*1)n (we know that for any value of n to end with 0 it should be in the form of (2*5)n )

So (3*1)n cannot and will never end with 0

For example 3*3=9

3*3*3=27

3*3*3*3=81

3*3*3*3*3=243

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So by this we can see it will never end with 0

Please mark me as brainliest