Question

show that the number 4(n) in when n is a natural number cannot end with the digit zero

Answer 1

hey here is ur ans .....

we have
4^n = (2×2)^n
= 2^n × 2^n


here the prime factorisation of 4^n does not contain 5 as factor . Hence , 4^n can never end with the digit 0 for any natural no.


hope it will help uh ...
nd plz mark as brainliest ...

Answer 2

Step-by-step explanation:

If any number ends with 0 then it must be divisible by 5

Hence its prime factorization must contain 5

But we know 4=2×2

So, there is no natural number n for which 4

n

can end with 0.