Question

show that the number 4^n,when n is a natural number can not end with the digit zero for any natural number,n

Answer 1

Answer:

given" n" is a rational number. Let 4^n ends with zero. then 4 is divisible by 5 but prime factors of 4 are 2 × 2. ... hence there is no natural number"n" for which 4^n ends with the digi

Answer 2

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