Show that the number 4n, when n is a natural number cannot end with the digit zero
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"If any number ending with the digit 0 in that prime factorisation 2 and 5 prime factors must be present" .
The prime factorisation of 4ñ = (2×2)ñ
In prime factorisation of 4ñ having only 2 as prime factor
So , 4ñ end with the digit "0" .
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