Question

show that the one and only one out of n,n+2,n+4 is
dividable by 3​

Answer 1

$\huge\mathbb\green{ANSWER}$

n+4 = 3q+2+4 = 3q+6 = 3(q+2) is divisible by 3. thus one and only one out of n , n+2, n+4 is divisible by 3.

Answer 2

Answer:

n+2 = 3q + 2+2 = 3q+4 = 3 ( q + 1 ) + 1 is not divisible by 3. n+4 = 3q + 2 + 4 = 3q + 6 = 3 (q+2) is divisible by 3. thus, one and only out of n, n+2, n+4 is divisible by 3.