Question

show that the origin is equidutant
from the lines 4x+3y+10=0 ,
5x-124 +26
+ 26 to and 7x+ 24 y = 50

Answer 1

Step-by-step explanation:

4x+3y+10=0 ---- (1)

5x-12y+26=0 ----- (2)

7x+24y=50 ------ (3)

The distance between origin & line (1) = ∣

16+9

4×0+30+10

∣=

5

10

=2

The distance between origin & line (2) = ∣

25+144

5×0−12×0+26

∣=

13

26

=2

The distance between origin & line (3) = ∣

(24)

2

+(7)

2

7×0+24×0−50

∣=

25

50

=2

∴ This distance between origin & all three lines is same.