show that the path of the projectile is parabola
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hello
Mathematically, they all follow aparabolic path, which is the pathfollowed by a projectile. If you are wondering, a projectile is an object that is only acted on by gravity. In math, a parabola is a curve that is the graphical representation of a quadratic equation.
eq of path of projectile is s=ucos@ -gt2/2
if two projectiles are projected from horizontal ground with different initial velocity and angle....both these quantities are known then at any time t
coordinates of A, S1=(UacosA)t i - gt2/2 j
coordinates of B, S2=(UbcosB)t i - gt2/2j
coordinates of A wrt to B is S2-S1=t(UacosA-UbcosB)i + 0 j
Xi + Yj = kt i + 0j (UacosA-UbcosB = constant=k)
ie X=kt is a straight line
hope this helps friend !!!
Mathematically, they all follow aparabolic path, which is the pathfollowed by a projectile. If you are wondering, a projectile is an object that is only acted on by gravity. In math, a parabola is a curve that is the graphical representation of a quadratic equation.
eq of path of projectile is s=ucos@ -gt2/2
if two projectiles are projected from horizontal ground with different initial velocity and angle....both these quantities are known then at any time t
coordinates of A, S1=(UacosA)t i - gt2/2 j
coordinates of B, S2=(UbcosB)t i - gt2/2j
coordinates of A wrt to B is S2-S1=t(UacosA-UbcosB)i + 0 j
Xi + Yj = kt i + 0j (UacosA-UbcosB = constant=k)
ie X=kt is a straight line
hope this helps friend !!!
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its not possible
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H and ab is not equal so it forms a parabola
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