Show that the paths represented by the equations x – 3y = 2 and –2x + 6y = 5 are parallel.
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Step-by-step explanation:
We know our standard linear equation is y=m*x+c
Hera m=slope
If slopes of these two equations are same then these ara parallel
First take x-3*y=2
x-2=3*y
3*y=x-2
y=(x-2)/3
y=1/3*x-2/3
So here slope is 1/3.
Then, -2*x+6*y=5
6*y=5+2*x
y=(5+2*x)/6
y=1/3*x+5/6
Here slope is also 1/3.
Both slopes are equal.
Then these two paths are parallel.
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