Question

Show that the point (0, 9) is equidistant
from the points (-4,1) and (4.1)​

Answer 1

Answer:

Let P(x,y,z) be any point which is equidistant from A(0,2,3) and B(2,−2,1).

Then,

PA=PB

PA

2

=PB

2

(x−0)

2

+(y−2)

2

+(z−3)

2

=

(x−2)

2

+(y+2)

2

+(z−1)

2

4x−8y−4z+4=0

x−2y−z+1=0

Hence, the required locus is x−2y−z+1=0.