show that the point (-4,-1) ,(-2,-4), (4,0)&(2,3) are the vertices points of a rectangle
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A(−4,−1), B(−2,4), C(4,0) and D(2,3) be the given points
we know that, distance formula = √(x_2-x_1)²+(y_2-y_1)²
Now, AD= √(2+4)²+(3+1)²= √52
BC= √(4+2)²+(0+4)²= √52
AB= √(−2+4)²+(−4+1)² = √4+9 = √13
CD= √(2−4)² +(3−0)² = √13
⇒ AD=BC and AB=CD
Now, AC= √(4+4)² +(0+1)² = √65
BD= √(2+2)² +(3+4)² = √65
⇒ AC=BD
Hence, ABCD is a rectangle
⇒ Therefore, the point (-4,-1) ,(-2,-4), (4,0)&(2,3) are the vertices points of a rectangle.
Hope this will help you...
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