Question

Show that the point (4, 4) is equidistant from the points A(1, 0) and
B(-1, 4)

Answer 1

Step-by-step explanation:

By distance formula

Distance between two points

$= \sqrt{ {(x2 - x1) }^{2} + {(y2 - y1)}^{2} }$

so, Distance between ( 4, 4 ) and

( 1, 0 )

$= \sqrt{ {(4 - 1)}^{2} + {(4 - 0)}^{2} }$

$= \sqrt{ {3}^{2} + {4}^{2} }$

$= \sqrt{9 + 16}$

$= \sqrt{25}$

$= 5 \: units$

Distance between ( 4, 4 ) and ( - 1, 4 )

$= \sqrt{ {(4 + 1)}^{2} + {(4 - 4)}^{2} }$

$= \sqrt{ {5}^{2} + {0}^{2} }$

$= \sqrt{25}$

$= 5units$

Hence ( 4, 4 ) is equidistant from

( 1, 0 ) and ( -1, 4 ).