show that the point A(0,0) B(6,0) D(9,4) and C(3,4) are the vertices of a parallelogram taken in order
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(i) Let point(0,7,−10),(1,6,−6) and (4,9,−6) be denoted by A,B and C respectively
AB=
(1−0)
2
+(6−7)
2
+(−6+10)
2
=
(1)
2
+(−1)
2
+(4)
2
=
1+1+16
=
18
Answered by
1
dont consider the distance between diagonals step
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