Math, asked by Atchitha06, 10 months ago

show that the point a(1,10) b(5,3) c(2,7) d(-2,4) are the vertices of a rhombus

Answers

Answered by kalinayak10

please check your question your question is wrong I think

Answered by Anonymous

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^__^, a(1,0),b(5,3),c(2,7),d(-2,4)

Distance

ab=root(5-1)^2+(3-0)^2

ab=root(4)^2+(3)^2

ab=root16+9

$ab = \sqrt{25}$

ab=5

bc=root(2-5)^2+(7-3)^2

bc=root(-3)^2+(4)^2

bc=root9+16

bc=root25

bc=5

cd=root(-2-2)^2+(4-7)^2

cd=root(-4)^2+(-3)^2

cd=root16+9

cd=root25

cd=5

ad=root(1+2)^2+(0-4)^2

ad=root(3)^2+16

ad=root9+16

ad=5

ac=root(2-1)^2+(7-0)^2

ac=root(1)^2+(7)^2

ac=root1+49

ac=root50

$ac = 5 \sqrt{2}$

bd=root(-2-5)^2+(4-3)^2

bd=root(-7)^2+1

bd=root49+1

bd=root50

$bd = 5 \sqrt{2}$

......... ac=bd......

Therefore abcd is a rhombus

(1,10) b(5,3) c(2,7) d(-2,4) are the vertices of a rhombus

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