Show that the points (0, 7, 10), (1, 6, 6) and (4, 9, 6) form an isosceles right-angled triangle
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Step-by-step explanation:
let the vertices of the triangle be A, B, & C
A = ( 0,7,10) B = ( 1,6,6) C = (4,9,6)
AB = 1 + 1 + 16 = 3 root2
BC = 9 + 9 = 3root2
AC = 16 + 4 + 16 = root36 = 6
two sides are equal so it is an isosceles tiangle
according to pythagarous therom
AC^2 = AB^2 + BC^2
6^2 = ( 3 root2 )^2 + ( 3 root2 )^2
36 = 18 + 18
36 = 36
so the given points can form an isosceles right angled triangle
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