Show that the points (1.0), (0.1) and (-3,4) lie on a straight line
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Step-by-step explanation:
Let the points be A(4, 2), B(7, 5) and C(9, 7). By the distance formula
AB
2
=(4−7)
2
+(2−5)
2
=(−3)
2
+(−3)
2
=9+9=18
BC
2
=(9−7)
2
+(7−5)
2
=2
2
+2
2
=4+4=8
CA
2
=(9−4)
2
+(7−2)
2
=5
2
+5
2
=25+25=50
So, AB=
18
=
9×2
=3
2
;BC=
8
=
4×2
=2
2
;CA=
50
=
25×2
=5
2
This gives AB+BC=3
2
+2
2
=5
2
=AC. Hence the points A, B and C are collinear.
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