show that the points ( 1,2 ), ( 2,1 ), ( -2,5 ) lie on the same line i.e,
collinear
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- For the Points (Vertices of Triangle) to be Collinear, The Area of Triangle should be 0
Area of Triangle = 1/2 [x₁ (y₂ - y₃ ) + x₂ (y₃ - y₁ ) + x₃(y₁ - y₂)]
We have :
- x₁ = 1 , x₂ = 2 , x₃ = -2
- y₁ = 2 , y₂ = 1 , y₃ = 5
⇒ Area of Triangle = 1/2 [x₁ (y₂ - y₃ ) + x₂ (y₃ - y₁ ) + x₃(y₁ - y₂)]
⇒ Area of Triangle = 1/2 [1 (1 - 5) + 2 (5 - 2 ) + (-2)(2 - 1 )]
⇒ Area of Triangle = 1/2 [1 (-4) + 2(3) -2(1)]
⇒ Area of Triangle = 1/2 [-4 + 6 - 2]
⇒ Area of Triangle = 1/2 [0]
⇒ Area of Triangle = 0/2
⇒ Area of Triangle = 0
As The Area of Triangle is 0, We showed the given points are collinear
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