Question

Show that the points (-1, -8) (4, -6) (2, -1) and (-3, -3) form a square

Answer 1

Answer:

let the points be ABCD respectively

for AB,  x1=-1 x2=4 y1= -8 y2= -6

using distance formula,

AB=√((x2-x1)²+(y2-y1)²)

or, AB=√25+4

=√29 units

again for CD, x1=2  x2= -3 y1= -1 y2= -3

using distance formula, CD=√((x2-x1)²+(y2-y1)²)

or, CD=√(-5)^2+(-2)^2

or, CD= √29 units

again for AD, x1= -1 x2= -3 y1= -8 y2= -3

using distance formula, AD=√((x2-x1)²+(y2-y1)²)

or, AD= √(-2)^2 + (-5)^2

or, AD= √29 units again for BC x1= 4 x2= 2 y1= -6 y2= -1

or BC=√29 units

here AB=BC=CD=AD=√29 units therefore it is square beause all the sides are equal

Step-by-step explanation: